Two identical non-re,aticivistic particles move at right angle to each other. Possesing de Broglie wavelength `lambda_(1)` and `lambda_(2)` Find the Broglie wavelength of each particle in the frame of their centre of inertia.
Two identical non-relativitic partcles A and B move at right angles to each othre, processing de Broglie wavelengths lamda_1 and lamda_2 , respectively. The de Broglie wavelength of each particle in their centre of mass frame of reference is
The de Broglie wavelength lambda of a particle
The de Broglie wavelength (lambda) of a particle is related to its kinetic energy E as
Two particles move at right angle to each other.Their de Broglie wavelengths are lambda_(1) and lambda_(2) respectively.The particles suffer perfectly inelastic collision.The de Broglie wavelength lambda of the final particle is given by :
If particles are moving with same velocity , then maximum de - Broglie wavelength will be for
The ratio of the de Broglie wavelength of a proton and alpha particles will be 1:2 if their
Two particles of de-broglie wavelength lamda_(x) and lamda_(y) are moving in opposite direction. Find debroglie wavelength after perfectly inelastic collision:
Two particles A and B of de-broglie wavelength lambda_(1) and lambda_(2) combine to from a particle C. The process conserves momentum. Find the de-Broglie wavelength of the particle C. (The motion is one dimensional).
