Two deuterons udnergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)
Nuclear energy is released in fission since binding energy per nucleon is
Nuclear energy is released in fusion reaction, since binding energy per nucleon is
In fusion reaction ._(1)H^(2) + ._(1)H^(2) to ._(2)He^(4) + Q Find the energy released while binding energy per nucleon for deuterium is 1.12 MeV and for helium nucleus is 7.07 MeV
if the binding energy per nucleon of deuteron is 1.115 Me V , find its masss defect in atomic mass unit .
If the binding energy per nucleon of deuterium is 1.115 MeV, its mass defect in atomic mass unit is
Assertion : Binding energy per nucleon is of the order of MeV. Reason: 1 MeV=1.6xx10^-13J .
The mass defect for the nucleus of helium is 0.0303 a.m.u. What is the binding energy per nucleon for helium in MeV ?
When two dentrons (._(1)H^(2)) fuse to from a helium nucleus ._(2)He^(4), 23.6 MeV energy is released. Find the binding energy of helium if it is 1.1 MeV for each nucleon of deutrim.
