In the adjacent figure `DeltaABC and DeltaDBC` are two triangles such that `bar(AB) = bar(BD)` and `bar(AC) = bar(CD)` . Show that `DeltaABC ~= DeltaDBC.`

In the figure, ΔABC and ΔABD are two triangles on the same base AB. If line segment CD is bisected by bar(AB) at O, show that ar (DeltaABC) = ar (DeltaABD).

DeltaABC and DeltaDBC are two isosceles triangles on thesame base BC (see figure). Show that /_ ABD = /_ ACD.

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the adjacent figure DeltaABC is isosceles as bar(AB) = bar(AC), bar(BA) and bar(CA) are produced to Q and P such that bar(AQ) = bar(AP) . . Show that bar(PB) = bar(QC) .

In the adjacent figure DeltaABC, D is the midpoint of BC. DE_|_AB, DF_|_AC and DE = DF . Show that DeltaBED ~= Delta CFD .

Prove the following Boolean relations: A+AB+bar(A)B= bar(bar(A)bar(B)

In the figure D, E are points on the sides AB and AC respectively of DeltaABC such that ar(DeltaDBC) = ar(DeltaEBC) . Prove that DE || BC.

Prove the following boolean relations. AB + Abar(B) + bar(A)bar(B) = A + bar(B)

Let's try and find the answers : (vii) Are the bar(AB) and bar(BA) same?

DeltaABC is an isosceles triangle in which AB = AC. Show that /_ B = /_ C.