ABCD is trapezium in which `AB"||"CD`. If `AD =BC`, show that `angleA=angleB` and `angleC = angleD`.

ABCD is a cyclic Trapezium whose AB|| CD. If angleABC = 75^@ , then angleBCD

ABCD is a cyclic trapezium having AD||BC. If angleABC = 70^@ then angleBCD=?

If in triangleABC a=2b and angle A=3 angleB then angleA=

ABCD is cyclic trapezium such that AD||BC, If angleABC =70^@ then the value of angleBCD is___

ABCD is a cyclic trapezium, AD||BC and angleABC = 70^@ , then angleBCD =

ABCD is a trapezium in which AB || DC and E is the mid-point of AD. If F be a point on BC such that EF || DC, then prove that EF=1/2(AB+DC).

ABCD is a cyclic trapezium in wich the sides AD and BC are parallel . If angleABC=75^(@) then find the value of angleBCD .

If ABCD be a cyclic quadrilateral in which angleA = 4x^@ , angleB = 7x^@ , angleC = 5y^@ & angleD = y^@ , then x, y is___

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

ABCD is a cyclic trapezium with AD∥BC. If ∠B=70 then determine other three angles of the trapezium.