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In DeltaABC, angleABC = 90^@ , AD = DC, ...

In `DeltaABC, angleABC = 90^@ , AD = DC, AB = 12cm and BC = 6.5` cm. Find the area of `DeltaADB` .

Answer

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(iv) In Delta ABC, angle ABC=90^@ and if AB=6 cm and BC= 8 cm , then find circum-radius of DeltaABC .

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Knowledge Check

  • In DeltaABC, angleABC=90^@ and AB =6 cm, BC =8 cm. Then the length of the circumradius of DeltaABC is

    A
    6 cm
    B
    5 cm
    C
    4 cm
    D
    3 cm

  • In DeltaABC, angleABC =90^@ , AB =6 cm, BC =8 cm. The length of the circum -radius of ABC is

    A
    10 cm
    B
    8 cm
    C
    6 cm
    D
    5 cm

  • In Delta ABC, AB=6sqrt(3)cm, AC= 12cm and BC = 6 cm. Then the value of /_B will be

    A
    `120^(@)`
    B
    `60^(@)`
    C
    `90^(@)`
    D
    `45^(@)`

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