A piece of wire 8 m. in length is cut into two pieces, and each piece is bent into a square. Where should the cut in the wire be made if the sum of the areas of these squares is to be `2m^(2)`?

A wire of length l is to be cut into to pieces, one being bent of form a square and the other to form a circle.How should the wire be cut if the sum of areas enclosed by the two pieces to be a minimum ?

Hydra cut into two pieces will result in

A wire of length 2 units is cut into two parts which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then :

A wire of length 28 m is to be cut into two pieces . One of the pieces is to be made into a square and the other into a circle . What should be the lengths of the two pieces so the two pieces so that the combined area of the circle and the square is minimum.

A wire of length 28 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a circle. What should be the length of the two pieces so that the combined area of the square and the circle is minimum?

A 45 cm long copper wire is bent to from a square. Let's find the length of one side of the square.

A wire of length 36 cm is cut into two pieces . One of the pieces will be bent into the shape of a square and the other into the shape of an equilateral triangle . Find the length of each piece so that the sum of the areas of the square and triangle is minimum.

A wire of length a is cut into two parts which are bent, respectively, in the form of a square and a circle. The least value of the sum of the areas so formed is (a^2)/(pi+4) (b) a/(pi+4) a/(4(pi+4)) (d) (a^2)/(4(pi+4))