The volume of spherical balloon being in...

The volume of spherical balloon being inflated changes at a constant rate.If initially its radius is 3 units and after 3 seconds it is 6 units. Find the radius of balloon after t seconds.

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The correct Answer is:

`(63 t + 27)^(1)/(3)`

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NCERT BANGLISH-DIFFERENTIAL EQUATIONS-EXERCISE - 9.4

sec^(2)x tan y dx + sec^(2) y tan x dy = 0
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(e^(x) + e^(-x))dy - (e^(x) - e^(-x)) dx = 0
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(dy)/(dx) = (1 + x^(2))(1 + y^(2))
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y log y dx - x dy = 0
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x^(5)(dy)/(dx) = - y^(5)
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For each of the differential equation find the general solution (dy)/(...
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e^(x) tan y dx + (1 - e^(x))sec^(2)y dy = 0
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For each of the differential equations in Exercises 11 to 14, find a p...
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x(x^(2) - 1)(dy)/(dx) = 1, y = 0 when x = 2.
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cos ((dy)/(dx)) = a (a ne R), y = 1 when x = 0
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(dy)/(dx) = y tan x, y = 1 when x = 0
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Find the equation of a curve passing through the point (0,0) and whose...
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For the differential equation xy(dy)/(dx) = (x + 2)( y + 2), find the ...
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Find the equation of a curve passing through the point (0, -2) given t...
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At any point (x,y) of a curve, the slope of the tangent is twice the s...
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In a bank, principal increases continuously at the rate of 5% per year...
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In a culture, the bacteria count is 1,00,000. The number is increased...
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The general solution of the differential equation (dy)/(dx) = e^(x + y...
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