In the adjacent figure `DeltaABC, D` is the midpoint of BC. `DE_|_AB, DF_|_AC` and `DE = DF`. Show that `DeltaBED ~= Delta CFD`.

In the adjacent figure, Delta ABC is right angled at C and DE bot AB . Prove that Delta ABC ~ Delta ADE and hence find the lengths of AE and DE ?

In the adjacent figure, we have AC = XD, C and D are mid points of AB and XY respectively. Show that AB = XY.

In the given figure AB || CD, BC || DE then find the values of x and y

In the figure, ABCD is a quadrilateral. AC is the diagonal and DE || AC and also DE meets BC produced at E. Show that ar(ABCD) = ar (DeltaABE).

In DeltaABC, D, E and F are the midpoints of sides AB, BC and CA respectively. Show that DeltaABC is divided into four congruent triangles, when the three midpoints are joined to each other. (ΔDEF is called medial triangle)

In Delta ABC , AB = AC and BC = 6cm, D is a point on the side AC such that AD = 5cm and CD = 4cm, show that Delta BCD ~ Delta ABC and hence find DB .

In Delta ABC, hat(A) =90^(@), AB = 4, AC = 3, D is the mid point of BC. Then BD is :

In a triangle ABC, if D and E are mid points of sides AB and AC respectively. Show that vecBE+ vecDC=(3)/(2)vecBC .

If D is the midpoint of AC and C is the midpoint of Ab, then find the length of AB if AD=4cm.