Home
Class 10
MATHS
Find the area of the quadrilateral whose...

Find the area of the quadrilateral whose vertices, taken in order, are (-4, -2), (-3, -5), (3, -2) and (2, 3).

Text Solution

Verified by Experts

The correct Answer is:
28 sq. units
Promotional Banner

Topper's Solved these Questions

  • COORDINATE GEOMETRY

    NCERT TAMIL|Exercise EXERCISE 7.4|8 Videos

  • COORDINATE GEOMETRY

    NCERT TAMIL|Exercise OPTIONAL EXERCISE|4 Videos

  • COORDINATE GEOMETRY

    NCERT TAMIL|Exercise EXERCISE 7.2|12 Videos

  • APPLICATIONS OF TRIGONOMETRY

    NCERT TAMIL|Exercise THINK AND DISCUSS|1 Videos

  • GEOMETRY

    NCERT TAMIL|Exercise UNIT EXERCISE - 4|5 Videos

Similar Questions

Explore conceptually related problems

Find the area of the quadrilateral whose vertices taken in order, are (-3, 2), (5, 4), (7,-6) and (-5, -4) .

Find the area of the quadrilateral whose vertices are at (-9, -2), (-8, -4), (2, 2) and (1, -3)

Find the area of the quadrilateral whose vertices are at (-9, 0), (-8, 6), (-1, -2) and (-6, -3)

Find the value of k, if the area of a quadrilateral is 28 sq.units, whose vertices are (-4, -2), (-3, k), (3, -2) and (2, 3)

Find the area of the triangle whose vertices are (0,0), (1,2) and (4,3).