The motion of a particle of mass m is described by `y =ut + (1)/(2) g t^(2)` . Find the force acting on the particale .

Explanation

We know
`y = ut + 1/2 "gt"^2`
`v = (dy)/(dt) = u + "gt"`
`a = (dv)/(dt) = g`
Then the force is given by eq.
F = ma = mg
Thus the given equation describes the motion of a particle under acceleration due to gravity and y is the position coordinate in the direction of g.