Determine the maximum acceleration of the train in which a box lying on its floor will remain stationary given that the coefficeient of static friction between the box and the train 's floor is 0.15 take `g=10ms^(-2)`

Explanation

Since the acceleration of the box is due to the static friction,
`ma = f_s lt= mu_s N = mu_s mg `
i.e, `a lt= mu_s g `
` therefore a_(max) = mu_s g = 0.15 xx 10 ms^(-2)`
` = 1.5 ms^(-2)`