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The molal elevation constant of water =0...

The molal elevation constant of water =`0.52 K m^(-1)`. The boiling point of `1.0 molal` aqueous `KCl` solution (assuming complete dissociation of `KCl`) should be

A

`100.52^(@)C`

B

`101.04^(@)C`

C

`99.48^(@)C`

D

`98.96^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta T_(b) =imk_(b)=0.52xx1xx2=1.04`.
`therefore T_(b)=100+1.04=101.04^(@)C`.
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