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0.15g of a substance dissolved in 15g of...

0.15g of a substance dissolved in 15g of a solvent boiled at a temp. higher by `0.216^(@)C` than that of the pure solvent. Find out the molecular weight of the substance `(K_(b)` for solvent is `2.16^(@)C`)

A

`1.01`

B

10

C

`10.1`

D

100

Text Solution

Verified by Experts

The correct Answer is:
D
`m=(K_(b)xxw xx 1000)/(Delta T_(b)xx W)=(2.16xx0.15xx1000)/(0.216xx15)=100`.
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