Elevation in boiling point was `0.52^(@)C` when 6 g of a compound X was dissolved in 100 g of water. Molecular weight of X is (`K_(b)` of water is `5.2^(@)C` per 100 g of water)

Options

A. 120
B. 60
C. 180
D. 600

Answer

B

Explanation

`Delta T_(b)=(100xx K_(b)xx w)/(m xx W) therefore 0.52=(100xx5.2xx6)/(m xx 100)`
`m=(100xx5.2xx6)/(0.52xx100)=60`.