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The boiling point of a solution of 0.11 ...

The boiling point of a solution of 0.11 of a substance in 15g of ether was found to be `0.1^(@)C` higher than that of pure ether. The molecular weight of the substance will be `(K_(b)=2.16)` :

A

148

B

158

C

168

D

178

Text Solution

Verified by Experts

The correct Answer is:
B
`m=(K_(b)xx w xx1000)/(Delta T_(b)xx W)`
`K_(b)=2.16, w=0.11, W=15 g, Delta T_(b) =0.1`
`m=(2.16xx0.11xx1000)/(0.1xx15)=158.40 ~= 158`.
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