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Dry air was passed successively through a solution of 5 gm of a solute in 80 gm of water and then through pure ware. The loss in weight of solution was 2.50 gm and that of pure solvent 0.04 gm. What is the molecular weight of the solute

A

`70.31`

B

`7.143`

C

`714.3`

D

80

Text Solution

Verified by Experts

The correct Answer is:
A
`m=(5xx18xx2.5)/(0.04xx80)=70.31`
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