Which of the following compounds corresponds Van't Hoff factor 'i' to be equal to 2 dilute solution

Options

A. `K_(2)SO_(4)`
B. `NaHSO_(4)`
C. Sugar
D. `MgSO_(4)`

Explanation

To determine which of the given compounds has a Van't Hoff factor (i) equal to 2 in dilute solutions, we need to analyze the dissociation of each compound in an aqueous solution. The Van't Hoff factor (i) represents the number of particles into which a compound dissociates in solution.

### Step-by-Step Solution:

1. **Understanding Van't Hoff Factor (i)**:
- The Van't Hoff factor (i) is defined as the number of particles into which a solute dissociates in solution. For a solute that does not dissociate, i = 1. For a solute that dissociates into multiple particles, i will be equal to the total number of particles formed.

2. **Analyzing Each Compound**:
- **Option 1: K₂SO₄**:
- Dissociation: K₂SO₄ → 2 K⁺ + SO₄²⁻
- Total particles = 2 (from K⁺) + 1 (from SO₄²⁻) = 3
- Therefore, i = 3.

- **Option 2: NaHSO₄**:
- Dissociation: NaHSO₄ → Na⁺ + H⁺ + SO₄²⁻
- Total particles = 1 (from Na⁺) + 1 (from H⁺) + 1 (from SO₄²⁻) = 3
- Therefore, i = 3.

- **Option 3: Sugar**:
- Sugar does not dissociate in solution.
- Therefore, i = 1.

- **Option 4: MgSO₄**:
- Dissociation: MgSO₄ → Mg²⁺ + SO₄²⁻
- Total particles = 1 (from Mg²⁺) + 1 (from SO₄²⁻) = 2
- Therefore, i = 2.

3. **Conclusion**:
- The only compound that corresponds to a Van't Hoff factor (i) equal to 2 is **MgSO₄**.

### Final Answer:
- The compound that corresponds to Van't Hoff factor 'i' equal to 2 in dilute solution is **MgSO₄**.