The density of a gas at `27^(@)C` and `1 atm` is `d`. Pressure remaining constant, at which of the following temperture will its density become `0.75 d`?

Options

A. `220^(@)C`
B. `30^(@)C`
C. 400 K
D. 300 K

Answer

C

Explanation

At constant pressure
`V prop nT prop (m)/(M) T`
`(V_(1))/(V_(2))=(m_(1)T_(1))/(m_(2)T_(2)):. (T_(1))/(T_(2))=(V_(1))/(m_(1))xx(m_(2))/(V_(2))=(d_(2))/(d_(1))implies (300K)/(T_(2))=(0.75d)/(d)`
`T_(2)=(300)/(0.75)=400K`