The maximum number of molecules is present in :

Options

A. 0.5g of `H_(2)` gas
B. 10 g of `O_(2)` gas
C. `15 L` of `H_(2)` gas at STP
D. 5L of `N_(2)` gas at STP

Answer

C

Explanation

In 22.4l of `H_(2)` maximum number of molecules `6.023 xx 10^(23)`
In 1l of `H_(2)` maximum number of molecules `=(6.023xx10^(23))/(22.4)`
In 15l of `H_(2)` maximum number of molecules `=(6.023xx10^(23))/(22.4)xx15=4.03 xx 10^(23)` molecules