A sample of gas occupies `100 mL` at `27^(@)C` and `740 mm` pressure. When its volume is changed to `80 mL` at `740 mm` pressure, the temperature of the gas will be

Options

A. `21.6^(@)C`
B. `240^(@)C`
C. `-33^(@)C`
D. `89.5^(@)C`

Answer

C

Explanation

`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2)):.T_(2)=(P_(2)V_(2))/(P_(1)V_(1))xxT_(1)=(740)/(740)xx(80)/(100)xx 300`
`= 240 K = - 33^(@)C`