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Two gases A and B having the same volume...

Two gases `A` and `B` having the same volume diffuse through a porous partition in `20` and `10` seconds respectively. The molar mass of `A` is `49 u`. Molar mass of `B` will be

A

`25.00` u

B

`50.00` u

C

`12.25 u`

D

`6.50 `u

Text Solution

Verified by Experts

The correct Answer is:
C

`(r_(A))/(r_(B))=sqrt((M_(B))/(M_(A)))implies (v_(A))/(t_(A))xx(t_(B))/(v_(B))=sqrt((M_(B))/(M_(B)))implies(10)/(20)=sqrt((M_(B))/(49))`
`implies (1)/(4) =(M_(B))/(49)`
`:. M_(B)=(49)/(4)=12.25`
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