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The average K.E. of an ideal gas is calo...

The average K.E. of an ideal gas is calories per mole is approximately equal to

A

Three times the absolute temperature

B

Absolute temperature

C

Two times the absolute temperature

D

1.5 times the absolute temperature

Text Solution

Verified by Experts

The correct Answer is:
A
`K.E. = (3)/(2). RT = (3)/(2).2.T " ":'R ~=2 calK^(-1)mol^(-1)`
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