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In the given reaction .(92)U^(235) overs...

In the given reaction `._(92)U^(235) overset(-alpha)rarr (A) overset(-beta)rarr (B) overset(-beta)rarr (C)` isotopes are

A

A and C

B

`._(92)U^(235)` and C

C

A and B

D

A, B and C

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To solve the problem, we need to analyze the given nuclear reactions step by step, starting from Uranium-235 and tracking the changes in atomic number and mass number through the decay processes. ### Step 1: Identify the initial isotope The initial isotope is Uranium-235, denoted as \( _{92}^{235}U \). ### Step 2: Alpha decay In the first step, Uranium-235 undergoes alpha decay. An alpha particle (which consists of 2 protons and 2 neutrons) is emitted. - **Mass number change**: The mass number decreases by 4 (235 - 4 = 231). - **Atomic number change**: The atomic number decreases by 2 (92 - 2 = 90). Thus, the resulting isotope \( A \) is: \[ A = _{90}^{231}Th \quad (\text{Thorium-231}) \] ### Step 3: First beta decay Next, isotope \( A \) undergoes beta decay. In beta decay, a neutron is converted into a proton, and a beta particle (an electron) is emitted. - **Mass number change**: The mass number remains the same (231). - **Atomic number change**: The atomic number increases by 1 (90 + 1 = 91). Thus, the resulting isotope \( B \) is: \[ B = _{91}^{231}Pa \quad (\text{Protactinium-231}) \] ### Step 4: Second beta decay Finally, isotope \( B \) undergoes another beta decay. - **Mass number change**: The mass number remains the same (231). - **Atomic number change**: The atomic number increases by 1 (91 + 1 = 92). Thus, the resulting isotope \( C \) is: \[ C = _{92}^{231}U \quad (\text{Uranium-231}) \] ### Summary of isotopes - Initial isotope: \( _{92}^{235}U \) (Uranium-235) - After alpha decay: \( _{90}^{231}Th \) (Thorium-231) - After first beta decay: \( _{91}^{231}Pa \) (Protactinium-231) - After second beta decay: \( _{92}^{231}U \) (Uranium-231) ### Conclusion The isotopes involved in the reaction are: 1. Uranium-235 2. Thorium-231 3. Protactinium-231 4. Uranium-231 ### Final Answer The isotopes are \( _{92}^{235}U \) (Uranium-235) and \( _{92}^{231}U \) (Uranium-231), which are isotopes of Uranium. ---

To solve the problem, we need to analyze the given nuclear reactions step by step, starting from Uranium-235 and tracking the changes in atomic number and mass number through the decay processes. ### Step 1: Identify the initial isotope The initial isotope is Uranium-235, denoted as \( _{92}^{235}U \). ### Step 2: Alpha decay In the first step, Uranium-235 undergoes alpha decay. An alpha particle (which consists of 2 protons and 2 neutrons) is emitted. ...
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