The reaction,
`2A(g) + B(g)hArr3C(g) + D(g)`
is begun with the concentration of A and B both at an intial value of `1.00` M. When equilibrium is reached, the concentration of D is measured and found to be `0.25` M. The value for the equilibrium constant for this reaction is given by the expression:

Options

A. `"["(0.75)^(3)(0.25)"]"div"["(1.00)^(2)(1.00)"]"`
B. `"["(0.75)^(3)(0.25)"]"div"["(0.50)^(2)(0.75)"]"`
C. `"["(0.75)^(3)(0.25)"]"div"["(0.50)^(2)(0.25)"]"`
D. `"["(0.75)^(3)(0.25)"]"div"["(0.75)^(2)(0.25)"]"`

Answer

B

Explanation

`2A+BhArr3C+D`
`{:("Initial",1,1,0,0),(Eq.,1-0.50,1-0.25,0.75,0.25):}`
`K=((0.75)^(3)(0.25))/((0.50)^(2)(0.75))`