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In the reaction PCl(5)(g) hArr PCl(3)(...

In the reaction
`PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)`, the equilibrium concentrations of `PCl_(5)` and `PCl_(3)` are 0.4 and 0.2 mole `//` litre respectively. If the value of `K_(c)` is 0.5 , what is the concentration of `Cl_(2)` in moles `//` litre ?

A

`2.0`

B

`1.5`

C

`1.0`

D

`0.5`

Text Solution

Verified by Experts

The correct Answer is:
C

`K_(c)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(0.2xx x)/(0.4)=0.5.`
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