A quantity of `PCl_(5)` ws heated in a 10 litre vessel at `250^(@)C: PCl_(5_(g))hArrPCl_(3(g))+Cl_(3(g)).` At equilibrium the vessel contains 0.1 moles of `PCl_(5)0.20` mole of `PCl_(3)and 0.2` mole of `Cl_(2).` The equilibrium constant of the reaction is

Options

A. `0.02`
B. `0.05`
C. `0.04`
D. `0.025`

Answer

C

Explanation

`K_(c)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=((0.2)/(10)xx(0.2)/(10))/([0.1//10])=0.04.`