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One mole of pure ethyl alcohil was treat...

One mole of pure ethyl alcohil was treated with one mole of pure acetic acid at `25^(@)C` One -third of the acid changes into ester at equilibrium . The equilibrium constant for the reaction will be:

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
D

`C_(2)H_(2)OH+COOHtoCH_(3)COOC_(2)H_(5)+H_(2)O`
`{:("Initial conc.","1 mol","1 mol","0 mole","0 mole"),("At equlibrium", 1-2/3=1/3 "mol",1/3"mol",2/3"mol",2/3"mol"):}`
`K_(C)=((2)/(3)xx(2)/(3))/(1/2xx1/3)=4`
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