`NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g)`
In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant `K_(p)` ?

Options

A. `2500atm^(2)`
B. `50atm^(2)`
C. `100atm^(2)`
D. `200atm^(2)`

Answer

A

Explanation

`NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)`
`{:(1,0,0,"initially"),(1-alpha,alpha,alpha,"at equlibrium"):}`
According to question at the equlibrium
`alpha+alpha=100impliesalpha=50` atm.
`thereforeK_(P)=P_(NH_(3))xxP_(H_(2)S)=50xx50=2500atm^(2)`