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What is the equilibrium expression for t...

What is the equilibrium expression for the reaction`P_(4)(s)+50_(2)(g)hArrP_(4)O_(10)(s)`

A

`k_(c)=[O_(2)]^(5)`

B

`K_(c)=[P_(4)O_(10)]//[P_(4)][O_(2)]`

C

`K_(c)=[P_(4)O_(10)]//[P_(4)][O_(2)]^(5)`

D

`K_(c)=1//[O_(2)]^(5)`

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(4(s))+5O_(2(g))hArrP_(4)O_(10(s))`
`K_(c)=([P_(4)O_(10(s))])/([P_(4(s))][P_(2(g))]^(5))`
We know that concentration of a solid compnent is always taken as unity `K_(c)=(1)/([O_(2)]^(5))`
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