Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, `PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g))` If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of `PC1_(5)` is x, the partial pressure of `PC1_(3)` will be:

Options

A. `((x)/(x-1))P`
B. `((2x)/(1-x))P`
C. `((x)/(x-1))P`
D. `((x)/(1-x))P`

Answer

A

Explanation

`{:(PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))),(1" "0" "0),((1-x)" "x " "x):}`
`therefore"Partial pressure of" PCl_(3)=((x)/(x+1))P`