One mole of `N_(2)O(g)` at `300K` is kept in a closed container under one atmosphere. It is heated to `600K` when `20%` by mass of `N_(2)O_(4)(g)` decomposes of `NO_(2)(g)`. The resultant pressure

Options

A. `1.2` atm
B. `2.4` atm
C. `2.0` atm
D. `1.0` atm

Answer

C

Explanation

`{:("Initial",1,0),("no. of moles",,),("No. of moles",(1-0.2),0.4),("at equlibrium",,):}`
Total number of moles at equlibrium `=1.2`
Initially, `P_(1)V=n_(1)RTor 1xxV=1xxRT_(1)or V=RT_(1)`
At equlibrium, `P_(2)V=n_(2)RT_(2)`
`or,P_(2)=(1.2)/(V)RT_(2)=(1.2)/(RT_(1))RT_(2)=(1.2xx600)/(300)=2.4atm.`