Three moles of `PCl_(5)`, three moles of `PCl_(3)` and two moles of `Cl_(2)` are taken in a closed vessel. If at equilibium, the vessel has 1.5 moles of `PCl_(5)` the number of moles of `PCl_(3)` present in it is

Options

A. 6
B. `4.5`
C. 5
D. 3

Answer

B

Explanation

`PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))`
`{:("3",3,2,("Initially")),("(3-x)",(3+x),(2+x),("Aqulibrium")):}`
Given that, `(3-x)=1.5, thereforex=1.5,` Therefore no. of moles of `PCl_((g))Presentis =3+1.5=4.5`