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Equilibrium concentration of HI, I(2) an...

Equilibrium concentration of `HI, I_(2) and H_(2)` is 0.7, 0.1 and 0.1 M respectively. The equilibrium constant for the reaction, `I_(2)+H_(2)hArr 2HI` is :

A

36

B

49

C

`0.49`

D

`0.36`

Text Solution

Verified by Experts

The correct Answer is:
B
`K_(c)=([HI]^(2))/([H_(2)][I_(2)])=([0.7]^(2))/([0.1][0.1])=49`
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