5 moles of `SO_(2)`and 5 moles of `O_(2)` are allowed to react .At equilibrium , it was foumnd that `60%` of `SO_(2)` is used up .If the pressure of the equilibrium mixture is one aatmosphere, the parital pressure of `O_(2)` is :

Options

A. `0.52` atm
B. `0.21` atm
C. `0.41` atm
D. `0.82` atm

Answer

C

Explanation

Initially `underset(5)(2SO_(2(g)))+underset(5)(O_(2(g)))hArrunderset(0)(2SO_(3(g)))`
Degree of dissociation `=0.60`
`therefore` no of moles of `SO_(2)` at equlibrium =2
no of moles of `O_(2)` atequlibrium =3.5
no of moles of `SO_(3)` produced at equlibrium=3
`therefore pO_(2)=(3.5xx1)/(8.5)=0.41atm.`