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The solubility of CaF(2) is 2 xx 10^(-4)...

The solubility of `CaF_(2)` is `2 xx 10^(-4) "mole"//"litre"`. Its solubility product is

A

`2.0 xx 10^(-4)`

B

`4.0 xx 10^(-3)`

C

`4xx8.0 xx 10^(-12)`

D

`3.2 xx 10^(-11)`

Text Solution

Verified by Experts

The correct Answer is:
c
`K_(sp)` for `CaF_(2) = 4s^(3) = 4 xx [2 xx 10^(-4)]^(3) = 3.2 xx 10^(-11)`.
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