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Solubility product of PbC(2) at 298K is ...

Solubility product of `PbC_(2)` at 298K is `1.0 xx 10^(-6)` At this temperature solubility of `PbCI_(2)` in moles per litre is

A

`6.3 xx 10^(-3)`

B

`(0.25 xx 10^(-6))^1`/`3`

C

`3.0 xx 10^(-3)`

D

`4.6 xx 10^(-14)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(sp) = 4s^(3)`
`S = 3sqrt((K_(sp))/(4)) = 3sqrt((1.0 xx 10^(-6))/(4)) = 6.3 xx 10^(-3)`
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