If the concentration of `CrO_4^(2-)` ions in a saturated solution of silver chromate is `2xx10^(-4)` , solubility product of silver chromate will be:

Options

A. `4 xx 10^(-8)`
B. `8 xx 10^(-12)`
C. `12 xx 10^(-12)`
D. `32 xx 10^(-12)`

Answer

D

Explanation

`K_(sp)` of `Ag_(2)CrO_(4) = [Ag^(+)]^(2)[CrO_(4)^(--)]`
`CrO_(4)^(--) = 2 xx 10^(-4)` then `Ag^(+_ = 2 xx 2 xx 10^(-4)`
`K_(sp) = (4 xx 10^(-4)) (2 xx 10^(-4)) = 32 xx 10^(-12)`.