On addition of a solution containing `CrO_4^(2-)` ions to the solution of `Ba^(2+), Sr^(2+)`, and `Ca^(2+)` ions, the precipitate obtained first will be of

Options

A. `CaCrO_(4)`
B. `SrCrO_(4)`
C. `BaCrO_(4)`
D. Mixture of (a), (b), (c)

Answer

C

Explanation

When we added barium ion in chromate ion solution we obtained yellow ppt of `BaCrO_(4)`.
`BaCl_(2)+ K_(2)CrO_(4) rarr underset("Yellow ppt".)(BaCrO_(4)) darr + 2KCl`