The solubility of a springly soluble salt `AB_(2)` in water is `1.0xx10^(-5) mol L^(-1)`. Its solubility product is:

Options

A. `4 xx 10^(-15)`
B. `4 xx 10^(-10)`
C. `1 xx 10^(-15)`
D. `1 xx 10^(-10)`

Answer

A

Explanation

`{:(AB_(2)hArr,A^(+),+,2B^(-)),(,1 xx 10^(-5),,2 xx 10^(-5)):}`
`K_(sp) = [1 xx 10^(-5)] [2 xx 10^(-5)] = 4 xx 10^(-15)`