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Given the data at 25^(@)C, Ag + I^(-) t...

Given the data at `25^(@)C,`
`Ag + I^(-) to AgI + e^(-), E^(@) = 0.152V`, `Agto Ag^(+)+ e^(-), E^(@) = -0.800V` What is the value of log K-sp For AgI ? `((2.303 (RT)/(F) = 0.059V))`

A

`-8.12`

B

`+8.612`

C

`-37.83`

D

`-16.13`

Text Solution

Verified by Experts

The correct Answer is:
D

Applying
`E_(I^(-)|AgI|Ag)^(@) = E_(Ag^(+)|Ag)^(@) + 0.059 log K_(sp) (AgI)`
`log K_(sp) (AgI) = (E_(I^(-)|AgI|Ag)-E_(Ag^(+)|Ag))/(0.09) = (-0.152-0.8)/(0.059) = -16.13`
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