The solubility of silver chromate in `0.01 M K_(2) CrO_(4)" is " 2 xx 10^(-8)` mol/1. The solubility product of silver chromate will be

Options

A. `8 xx 10^(-24)`
B. `16 xx 10^(-24)`
C. `1.6 xx 10^(-18)`
D. `16 xx 10^(-18)`

Answer

D

Explanation

`{:("Given " K_(2)CrO_(4),hArr,2K^(+),+,CrO_(4)^(2-)),("Conc. "0.01,,0.02,,0.01),("and for "Ag_(2)CrO_(4),,,,):}`
`{:(Ag_(2)CrO_(4),hArr,2Ag^(+)+,CrO_(4)^(2-)),(S,,2S,S+0.1):}`
`K_(sp) = [Ag^(+)][CrO_(4)^(2-)]`
`K_(sp) = (2S)^(2)(S + 0.01) rArr 4S^(2) [S + 0.01]`
? `K_(sp) = 4[2 xx 10^(-8)]^(2) xx 0.01 [[2 xx 10^(-8)]^(2) lt lt 0.01]`
`K_(sp) = 4 xx 4 xx 0.01 xx 10^(-16), K_(sp) = 16 xx 10^(-18)`