If the rate of a reaction is "5" at \(10^{o}C\),then on increasing the temperature to \(30^{o}C\) ,new rate is "

Options

A. 20
B. 10
C. 50
D. 40

Answer

a

Explanation

For every `10^(@)` rise of temperature rate constant doubles .
For `20^(@)` rise of temperature , rate constant becomes 4 times ,
i.e., `k_(2) = 4k_(1) = 4 xx 5 = 20.`