The half-life of `2` sample are `0.1` and `0.4` seconds. Their respctive concentration are `200` and `50` respectively. What is the order of the reaction

Options

A. 0
B. 2
C. 1
D. 4

Answer

b

Explanation

`t_(1//2) prop a^(1-n) implies (0.1)/(0.4) = ((200)^(1-n))/((50)^(1-n)) implies (1)/(4) [(4)/(1)]^(1-n) = [(1)/(4)]^(n-1)`
`implies (1)/(4^(1)) = (1)/(4^(n-1)) therefore n - 1 = 1 , n = 2`.