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In the reaction 2N(2)O(5) rarr 4NO(2) + ...

In the reaction `2N_(2)O_(5) rarr 4NO_(2) + O_(2)`, initial pressure is `500 atm` and rate constant `K` is `3.38 xx 10^(-5) sec^(-1)`. After `10` minutes the final pressure of `N_(2)O_(5)` is

A

490 atm

B

250 atm

C

480 atm

D

420 atm

Text Solution

Verified by Experts

The correct Answer is:
a
`p_(0) = 500 ` atm , `K = (2.303)/(t) "log"_(10) (p_(0))/(p_(t))`
`3.38 xx 10^(-5) = (2.303)/(10 xx 60) "log" (500)/(p_(t))`
or `0.00880 `= log `(500)/(p_(t)) implies (500)/(1.02) = 490` atm .
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