Which of the following compounds will show geometrical isomerism

Options

A. Cyclohexene
B. 2-hexene
C. 3-hexyne
D. 1, 1-diphenylethylene

Explanation

To determine which of the given compounds will show geometrical isomerism, we need to analyze each compound based on the presence of a double bond (C=C) or a cyclic structure, and the substituents attached to the carbon atoms involved in the double bond or the ring.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- Cyclohexene
- 2-Hexene
- 3-Hexene
- 1,1-Diphenyl ethylene

2. **Analyze Each Compound for Geometrical Isomerism**:
- **Cyclohexene**:
- Cyclohexene is a cyclic compound with a double bond. However, due to the symmetry of the cyclohexene ring, it does not have different substituents on either side of the double bond. Therefore, it cannot exhibit geometrical isomerism.

- **2-Hexene**:
- In 2-hexene, the double bond is between the second and third carbon atoms. The substituents on these carbons can be different (for example, one side can have a methyl group and the other side can have a hydrogen atom). This allows for the possibility of cis and trans isomers, thus 2-hexene can show geometrical isomerism.

- **3-Hexene**:
- In 3-hexene, the double bond is also between the third and fourth carbon atoms. Similar to 2-hexene, the substituents can be different on either side of the double bond. Therefore, 3-hexene can also exhibit geometrical isomerism.

- **1,1-Diphenyl ethylene**:
- In 1,1-diphenyl ethylene, both substituents on the double bond are phenyl groups (C6H5). Since both substituents are the same, this compound cannot exhibit geometrical isomerism.

3. **Conclusion**:
- The compounds that can show geometrical isomerism are **2-Hexene** and **3-Hexene**. Cyclohexene and 1,1-diphenyl ethylene do not exhibit geometrical isomerism.

### Final Answer:
The compounds that will show geometrical isomerism are **2-Hexene** and **3-Hexene**.

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