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Prove that ( " cos " 4x + " cos " 3x ...

Prove that `( " cos " 4x + " cos " 3x + " cos " 2x)/(" sin " 4x + " sin " 3x + " sin " 2x) = " cot 3x`

Text Solution

AI Generated Solution

To prove that \[ \frac{\cos 4x + \cos 3x + \cos 2x}{\sin 4x + \sin 3x + \sin 2x} = \cot 3x \] we will start by simplifying the left-hand side (LHS). ...
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Knowledge Check

  • The expression ("cos" 4x+"cos" 3x+"cos"2x)/("sin" 4x+"sin" 3x+ "sin" 2x) is equal to

    A
    `-cot 3x`
    B
    cot 3x
    C
    cot 2x
    D
    `-cat 2x`

  • (" sin 8x cos x- sin 6x cos 3x")/(" cos 2x cos x - sin 4x sin 3x")=

    A
    ` " sin " 2x`
    B
    ` " cos " 2x`
    C
    ` " tan " 2x`
    D
    ` " cosec " 2x`

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