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A current I flows through a long straigh...

A current I flows through a long straight conductor which is bent into a circular loop of radius R in the middle as shown in the figure .

The magnitude of the net magnetic field at point O will be

A

Zero

B

`(mu_0I)/(2R)(1+pi)`

C

`(mu_0I)/(4piR)`

D

`(mu_0I)/(2R)(1-1/pi)`

Text Solution

Verified by Experts

The correct Answer is:
d

[Hint: Field at O due to long straight conductor , `B_(1)=(mu_0I)/(2piR)o.` and field at O due to circular loop `B_(2)=(mu_0I)/(2R)ox . :.` Net magnetic field at O, `B=B_(2)-B_(1)=(mu_0I)/(2R)(1-1/pi)ox` ]
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