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The kinetic energy of a proton and that ...

The kinetic energy of a proton and that of an `alpha` - particle are 4 eV and 1 eV , respectively . The ratio of the de - Broglie wavelengths associated with them , will be

A

`2:1`

B

`1:1`

C

`1:2`

D

`4:1`

Text Solution

Verified by Experts

The correct Answer is:
b
[Hint : As per relation `lamda_(de)=h/(sqrt(2mK)),lamda_p/lamda_(alpha)=sqrt((m_alphaK_(alpha))/(m_pK_(p)))=sqrt((4m_pxx1eV)/(m_pxx4eV))=1`]
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