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Determine the equivalent resistance of n...

Determine the equivalent resistance of networks shown in Fig. (i) and (ii).

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(i) The circuit contains four identical elements joined in series. One such element is shown in Fig. and has two branches, having resistance of 2 `Omega (i.e., 1 Omega +2 Omega)` and 4 12 (i.e., 212 +212) respectively, joined in parallel.
` therefore ` Resistance of the element `R = (2 xx 4)/(2 + 4) = 8/6 = 4/3 Omega`
For whole series net equivalent resistance = `4R = 4 xx4/3 = 16/3Omega`
(ii) The combination shown has five resistances all joined in series. The total resistance is, thus, 5R.
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