A cell of emf 2.0 V and internal resistance 0.1 `Omega` is connected with a resistance of 3.9`Omega`. The voltage across the cell terminals will be

Options

A. 0.50 V
B. 1.90 V
C. 1.95 V
D. 2.0 V

Answer

C

Explanation

`V = (epsi R)/((R + r))= (2.0 xx 3.9)/((3.9 + 0.1)) = 1.95 V`